if the length of a rectangle is 12 feet and breadth is 18 what is the perimeter of the rectangle
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Answers
Answered by
1
Step-by-step explanation:
Given
length of rectangle,l=12 feet
width of rectangle,b=18 feet
perimeter of rectangle =2(l+b)
=2(12+18)
=2(30)=60feet
Answered by
2
Answer:
2a+ 2b = 12; a + b = 6
2c + 2d = 18; c + d = 9
ab = cd
a(6-a) = c(9-c) = area
c = 1, area = 8
6a — a^2 = 8
a^2 — 6a + 8 = 0
(a — 4)(a— 2) = 0
Therefore, a is either 2 or 4. b is either 4 or 2, respectively.
Therefore, c = 1, d = 8.
So, first rectangle is 2x4, second rectangle is 1x8.
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