Question

If the length of a Rectangle is 12cm , and breadth is 10 cm. Find the perimeter of the Rectangle.
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Answer 1

Answer:

44

Step-by-step explanation:

perimeter=2(l+b)

=2(12+10)

=2x22

=44 Ans.

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Answer 2

Rough Diagram :

$\begin{gathered}\begin{gathered} \begin{gathered} \sf{ \red{10 \: cm }\:}\huge\boxed{ \begin{array}{cc} \: \: \: \sf\footnotesize{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: }\\ \: \: \: \end{array}} \\ \: \: \: \: \: \sf{ \red{12 \: c m}}\end{gathered} \end{gathered} \end{gathered}$

Given :

• Length = 12cm
• Breadth = 10cm

To Find :

• Perimeter of Rectangle = ?

$\begin{gathered} \\ \\ \end{gathered}$

Solution:

$\green{♣}$Formula Used :

${\underline{\boxed{\sf{ Perimeter = 2 \bigg(Length + Breadth \bigg) }}}}$

Where :

• ➻ L = Length
• ➻ B = Breadth

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}\end{gathered}\end{gathered} \end{gathered}$

★ Calculating The Perimeter :

$\begin{gathered}\begin{gathered}\begin{gathered} {\dashrightarrow{\qquad{\sf{ Perimeter = 2 \bigg(Length + Breadth \bigg) }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ = 2 \bigg(10 + 12 \bigg) }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 2 \times10 +12 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 2 \times 22}}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ 22 \times 2 = 44 }}}} \ \\ \\ \\ \ {\qquad \; \; {\therefore \; {\underline{\boxed{\red{\pmb{\frak{ Perimeter = 44\; cm }}}}}}}} \end{gathered}\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \\ \qquad{\rule{150pt}{1pt}} \end{gathered}\end{gathered}\end{gathered} \end{gathered}$

★ Therefore :

❛❛ Perimeter of the given Rectangle is 44cm . ❜❜

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered} \\ {\underline{\rule{300pt}{9pt}}} \end{gathered}\end{gathered} \end{gathered} \end{gathered}$