Math, asked by Disha14951, 12 days ago

If the length of a rectangle is 14cm more than its breadth and its perimeter is 180cm, then area of the rectangle is what?​

49

Given :

• Length of rectangle is 14cm more than breadth of the rectangle.
• Perimeter of rectangle = 180cm

To find :

• The area of the rectangle.

Solution :

Let the Breadth of the rectangle be x cm

Then the Length will be x + 14 cm

★Perimeter of rectangle = 2( length + breadth)

Thus,

Putting the value :

⟼ 180 = 2( x + 14 + x)

⟼ 180 = 2(2x + 14)

⟼ 180 = 4x + 28

⟼ 180 - 28 = 4x

⟼ 152 = 4x

⟼ x = 152/4

⟼ x = 38

Therefore,

• The Breadth (x) of the rectangle is 38 cm
• And the Length (x + 14) of the rectangle is 38 + 14 = 52

----------------------------

Now , as we got the values of length and breadth of the rectangle . Let's start finding the Area of the rectangle.

★ Area of rectangle = length × breadth

A/Q

↬ Area of rectangle = 38 × 52

↬ Area of rectangle = 1976 cm².

Thus,

The area of the rectangle is 1976cm².

14

Given :-

• The length of a rectangle is 14 cm more than its breadth and its perimeter is 180 cm.

To Find :-

• The area of the rectangle ?

Step-by-Step-Explaination :-

Let length be l and breadth be b.

So,

I= b+ 14

As we know that :-

Perimeter of rectangle = 2 ( l + b )

Putting the respective value,

=>180 = 2( b + 14 + b )

=>180 = 2(2b + 14)

=>180 = 4b + 28

=>4b = 180 - 28

=>4b = 152

=>b = 38

Length = b + 14

=> l = 38 + 14

=> l = 52

Now,

As we know that :-

Area of rectangle = l × b

Putting the respective value,

Area of rectangle = 52 × 38

Area of rectangle = 1976 cm²

Hence Solved !

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