Question

If the length of a rectangle is 15cm and breadth is 5cm, what is its area?

Answer 1

Given : The Length of Rectangle is 15 cm & Breadth of Rectangle is 5 cm .

Exigency to find : Area of Rectangle.

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⠀⠀⠀⠀⠀ Finding Area of Rectangle :

$\dag\:\:\it{ As,\:We\:know\:that\::}$

$\qquad \dag\:\:\bigg\lgroup \sf{Area _{(Rectangle)} \:: l \times b }\bigg\rgroup$

⠀⠀⠀⠀⠀Here l is the Length of Rectangle & b is the Breadth of Rectangle .

⠀⠀⠀⠀⠀⠀$\underline {\boldsymbol{\star\:Now \: By \: Substituting \: the \: known \: Values \::}}$

$\qquad \longmapsto \sf Area = 15 \times 5$

$\qquad \longmapsto \frak{\underline{\purple{\:Area = 75 cm^2 }} }\bigstar$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {\:Area \:of\:Rectangle \:is\:\bf{75\:cm^2}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

$\qquad \leadsto \sf Area_{(Rectangle)} = Length \times Breadth$

$\qquad \leadsto \sf Perimeter _{(Rectangle)} = 2 (Length + Breadth)$

$\qquad \leadsto \sf Area_{(Square)} = Side \times Side$

$\qquad \leadsto \sf Perimeter _{(Square)} = 4 \times Side$

$\qquad \leadsto \sf Area_{(Trapezium)} = \dfrac{1}{2} \times Height \times (a + b )$

$\qquad \leadsto \sf Area_{(Parallelogram)} = Base \times Height$

$\qquad \leadsto \sf Area_{(Triangle)} = \dfrac{1}{2} \times Base \times Height$

$\qquad \leadsto \sf Area_{(Rhombus)} = \dfrac{1}{2} \times Diagonal _{1}\times Diagonal_{2}$

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Answer 2

Iength is 15 cm
Breadth is 5cm
Area =?
So, the area of a rectangle is l x b
Thus , 15 x 5 =75 cm^2
Area is 75 cm^2✌