If the length of a rectangle is 15cm more than it's width and the perimeter is 150cm find the dimensions of the rectangle . Factorise qus
Answers
Given that,
the length of a rectangle is 15cm more than it's breadth.
let the breadth of the rectangle be x.
therefore it's length = x + 15
perimeter of the rectangle is given = 150cm
formula to find the perimeter of a rectangle is 2(l + b)
so we can write,
➡2(l + b) = 150cm
➡ 2(x + 15 + x) = 150cm
➡ x + 15 + x = 150/2
➡ 2x + 15 = 75cm
➡ 2x = 75 - 15
➡ x = 60/2
➡ x = 30cm
hence the dimensions of the rectangle are :-
- breadth = x = 30cm
- length = x + 15 = 45cm
VERIFICATION :-
perimeter = 2(l + b)
= 2(45 + 30)
= 2 × 75
= 150cm
hence verified!
Length of rectangle is equal to 15 + b
Breadth of rectangle is equal to b
Perimeter is equal to 150
Equation
Perimeter is equal to 2 l + b
2 l + b is equal to p
2 into l + 15 + b is equal to 150
2b+ 30 + 2B is equal to 150
4B is equal to 150 - 30
4B is equal to 120
b is equal to 120 divided by 4
b is equal to 30
Therefore;
breadth is equal to b is equal to 30
length is equal to b + 15 is equal to 30 + 15 is equal to 45