Question

If the length of a rectangle is (2x+3) cm and width is (2x+1) cm, and if the perimeter of rectangle

is 168cm. Then find its area.​

Answer 1

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Answer 2

SOLUTION

GIVEN

• The length of a rectangle is (2x+3) cm and width is (2x+1) cm

• The perimeter of rectangle is 168cm.

TO DETERMINE

The area.

EVALUATION

Here it is given that length of a rectangle is (2x+3) cm and width is (2x+1) cm

So perimeter

= 2( 2x + 3 + 2x + 1 ) cm

= 2( 4x + 4 ) cm

So by the given condition

$\sf{2(4x + 4) = 168}$

$\sf{ \implies \: 8(x + 1) = 168}$

$\sf{ \implies \: (x + 1) = 21}$

$\sf{ \implies \: x = 20}$

So length = 43 cm and width = 41 cm

Hence the required area

= 43 × 41 cm²

= 1763 cm²

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