Math, asked by shashank1392, 2 months ago

If the length of a rectangle is (2x + 3) cm and width is (2x + 1) cm, and if the perimeter of rectangle is 168cm. Then find its area.​

Answers

Answered by itsraiabhishek
7

Answer:

Given: length = 17 cm, breadth = 13 cm

Perimeter of rectangle = 2 (length + breadth)

= 2 (17 + 13) cm

= 2 × 30 cm

= 60 cm

We know that the area of rectangle = length × breadth

= (17 × 13) cm2

= 221 cm2

Answered by amitnrw
0

Given : length of a rectangle is (2x + 3) cm and width is (2x + 1) cm, and   the perimeter of rectangle is 168cm.

To Find:  area.​

Solution:

length of a rectangle = (2x + 3) cm

width of a rectangle = (2x + 1) cm

Perimeter = 2( length + width )

= 2(2x + 3 + 2x + 1)

= 2(4x + 4)

= 8(x + 1)  cm

8(x + 1)   = 168

=> x + 1 = 21

=> x = 20

length of a rectangle = (2(20) + 3) = 43cm

width of a rectangle = (2(20) + 1) = 41 cm

Area = 43 * 41

= 1763 m²

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