Question

If the length of a rectangle is 2x meters and its area is (8x^2 - 10x) square meter, Then find it's breadth.

Answer 1

Answer:

Let the breadth=b

Length of the rectangale=2x meter

Area=l×b

(8x×2-10x) =(2x)×b

(8x-10x) = (2x)×b/2

-2x = xb

-2x/x = b

-2=b

b=(-2)

Answer 2

Answer:

$\frac{-5}{3}$

Step-by-step explanation:

$Breadth=(\frac{area}{length} ) units$

Let the breadth be $x$.

$A/Q: x=\frac{8x^2-10x}{2x}\\\\=> x*2x=8x^2-10x\\\\=>2x^2=8x^2-10x\\\\=>2x^2-8x^2=-10x\\\\=>-6x^2=10x\\\\=>-6x=-10\\\\=>x=\frac{-10}{6} \\\\=>x=\frac{-5}{3}$

∴ $breadth=x=\frac{-5}{3}$