Question

If the length of a rectangle is 3/2 times its width and its perimeter is 400 metres then find the length and width of the rectangle​

Answer 1

Answer:

Perimeter of a rectangle is 2(l+b)=400

l+b=200

Given that length and breadth are in the ratio 3:2

So length=120 and breadth =80

The area of a rectangle is l*b=120*80

There for area of a rectangle is 9600

Step-by-step explanation:

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Answer 2

The length of the rectangle is 120m

The width of the rectangle is 80m

Explanation:

Given:

1. The length of a rectangle is 3/2 times its width

2. The Perimeter is 400m

To find:

The length and width of the rectangle​

Formula:

Perimeter of the rectangle = 2(l+b)

Solution:

==> Let, length be l

==> the width of the rectangle be b

==> length is 3/2 times of its width

==> l = 3/2 b

==> Perimeter = 400m

==> P = 2(l+b)

==> 400 = 2(l+b)

==> $400=2(\frac{3}{2}b+b )$

==> $400=2(\frac{3b+2b}{2} )$

==> 400 = 3b+2b

==> 400 = 5b

==> b = 80 m

==> $l=\frac{3}{2}b$

==> $l=\frac{3}{2}\times80$

==> l = 3×40

==> l = 120 m

The length of the rectangle is 120m

The width of the rectangle is 80m