If the length of a rectangle is 5 cm more than the breadth and the perimeter of the rectangle is 40 cm.find the length ajd breadth
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Let the breadth be x
Length= (x+5)cm
Perimeter=40cm
Perimeter= 2(l+b)
40= 2{(x+5)+(x)}
40=2x+10+2x
40=4x+10
4x=40-10
4x =30
x=30÷4
x =7.5
Breadth=7.5cm
Length= 7.5+5= 12.5cm
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Length= (x+5)cm
Perimeter=40cm
Perimeter= 2(l+b)
40= 2{(x+5)+(x)}
40=2x+10+2x
40=4x+10
4x=40-10
4x =30
x=30÷4
x =7.5
Breadth=7.5cm
Length= 7.5+5= 12.5cm
Hope I helped u
Pls mark it as brainliest.☺
Answered by
119
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The length of a rectangle is 5cm more than its breadth.If the perimeter of the rectangle is 70cm.Find its length and breadth.
Let the breadth of rectangle be x cm.
Then its length = x + 5 cm
Perimeter = 2 (Length + Breadth)
70 = 2 (x + (x+5)
=2x + 5
2x + 5 = 35
2x = 35 - 5 = 30
x =
Breadth = x = 15cm.
Length = x + 5 = 15 + 5 = 20cm
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