Math, asked by PrinceRobinhood, 1 year ago

if the length of a rectangle is increased by 20percent and breadth decrease by 20 percent then the new area

Answers

Answered by kaushikvidit007
14
Let L = 10
Let W = 10 (a square is a rectangle)

Original area = (LW) = 10*10 = 100

L increases by 20 percent: 
(1.2)(10) = 12

W decreases by 20 percent:
(0.8)(10) = 8

New area: (12)*(8) = 96

Percent change:New−OldOld∗100New−OldOld∗100

96−100100=96−100100= 
(−.04)∗100(−.04)∗100 = 4 percent decrease

Algebra
L = length
W = width
Area = (1)LW

Length increases by 20 percent, width decreases by 20 percent:

1.2L * 0.8W = (.96) LW

.96 is 4 percent less than 1

The area decreases by 4 percent.
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Answered by wifilethbridge
10

The area of rectangle is decreased by 4%

Step-by-step explanation:

Let the original length be x

Let original breadth be y

Area of original rectangle = Length \times Breadth = xy

The length of a rectangle is increased by 20percent

New Length = x+\frac{20}{100}x=1.2x

The breadth decrease by 20 percent

New Breadth = y-\frac{20}{100}y=0.8y

New Area = Length \times Breadth =(1.2x)(0.8y)=0.96xy

Difference in original and new area = xy=0.97xy = 0.04 xy

Change in percentage in area = \frac{0.04xy}{xy} \times 100

                                                   = 4\%

Hence The area of rectangle is decreased by 4%

#Learn more :

https://brainly.in/question/12264368

If the length of a given rectangle is increased by 20percent and the breadth is decreased by 20percent then the result of area is

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