Question

if the length of a rectangle is increased by 20percent and breadth decrease by 20 percent then the new area

Answer 1

Let L = 10
Let W = 10 (a square is a rectangle)

Original area = (LW) = 10*10 = 100

L increases by 20 percent: 
(1.2)(10) = 12

W decreases by 20 percent:
(0.8)(10) = 8

New area: (12)*(8) = 96

Percent change:New−OldOld∗100New−OldOld∗100

96−100100=96−100100= 
(−.04)∗100(−.04)∗100 = 4 percent decrease

Algebra
L = length
W = width
Area = (1)LW

Length increases by 20 percent, width decreases by 20 percent:

1.2L * 0.8W = (.96) LW

.96 is 4 percent less than 1

The area decreases by 4 percent.
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Answer 2

The area of rectangle is decreased by 4%

Step-by-step explanation:

Let the original length be x

Let original breadth be y

Area of original rectangle = $Length \times Breadth = xy$

The length of a rectangle is increased by 20percent

New Length = $x+\frac{20}{100}x=1.2x$

The breadth decrease by 20 percent

New Breadth = $y-\frac{20}{100}y=0.8y$

New Area = $Length \times Breadth =(1.2x)(0.8y)=0.96xy$

Difference in original and new area = xy=0.97xy = 0.04 xy

Change in percentage in area = $\frac{0.04xy}{xy} \times 100$

                                                   = $4\%$

Hence The area of rectangle is decreased by 4%

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If the length of a given rectangle is increased by 20percent and the breadth is decreased by 20percent then the result of area is