If the length of a rectangle is twice its width and it is known that length of its diagonal is 15√10 cm. Then determine the area of the rectangle
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let b= X then l= 2X
dig=√(l²+b²)
15√10= √((2X)²+X²)
squaring both the sides
225×10= 4X²+X²
5X²= 2250
X²=450
X= √450
X=15√2
so breadth= 15√2 cm length = 30√2 cm
dig=√(l²+b²)
15√10= √((2X)²+X²)
squaring both the sides
225×10= 4X²+X²
5X²= 2250
X²=450
X= √450
X=15√2
so breadth= 15√2 cm length = 30√2 cm
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