Question

if the length of a rectangle is (x+2)cm and breath is (x+1)cm , find the area of rectangle ? ​

Answer 1

Answer:

Let the length of the rectangle be x units and the breadth be y units.

Area of the rectangle=length×breadth

=x×y=xy sq. units

From the given information, we have,

(x+2)×(y−2)=xy−28and(x−1)×(y+2)=xy+33(x+2)×(y−2)=xy−28=>xy−2x+2y−4=xy−28=>−2x+2y=−24=>−x+y=−12=>x=y+12....(i)Also,(x−1)×(y+2)=xy+33=>xy+2x−y−2=xy+33=>2x−y=35....(ii)

Substituting equation (i) in equation (ii), we get,

2x−y=35=>2(y+12)−y=35=>2y+24−y=35=>y=11

Substituting y=11 in equation (i), we get,

x=y+12=>x=11+12=>x=23

Therefore, length of rectangle =x=23 units

and breadth of rectangle 

Answer 2

Answer :-

• The area of the rectangle = (x² + 2x + 2) cm².

To find :-

• The area of the rectangle.

Step-by-step explanation :-

• Here, the length and breadth of a rectangle are given to us. We have to find it's area!

We know that :-

$\underline{\boxed{\sf Area_{(rectangle)} = Length \times Breadth}}$

Here,

• Length = (x + 2) cm.
• Breadth = (x + 1) cm.

Therefore,

$\bf Area = (x + 2) \: (x + 1)$

$\bf Area = (x) (x) + (x) (1) + (2) (x) + (2) (1)$

$\bf Area = (x^2) + (x) + (2x) + (2)$

$\bf Area = x^2 + x + 2x + 2$

$\bf Area = (x^2 + 3x + 2) \: cm^2$

Hence :-

• The area of the rectangle is (x² + 3x + 2) cm².

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