if the length of a rectangle is xcm more than its breadth such that its area is equal to 1 less than twice its perimeter, find the value of x , if the breadth is 7cm
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l=b+X cm
b=b
area=2×(2×(b+x+b))-1
=2 (2 (2b+x))-1
=2 (4b+2x)-1
now it's given
b=7 cm
area=2 (4×7+2x)-1
=2 (28+2x)-1
=56+4x-1
=55+4x
now
a/q
l×b=55+4x
(7+x )7=55+4x
49+7x=55+4x
7x-4x=55-49
3x=6
x=2
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