if the length of a rectangular field is increased by 60% then by what percent should the breadth be decreased so that thete is no change in area
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Step-by-step explanation:
Say l is the length
b is the breadth and
A is the area
A = lb....equ(1)
New length = L = 1.6×l
New breadth = B, to be found out
New area = Old area = A
A = LB = 1.6×l×B....equ(2)
From equ (1), l = A/b
Substitute in equ(2)
i.e. A = 1.6×A×B/b
or B/b = 1/1.6
or (B/b)-1 = (1/1.6)-1
(B-b)/b = -0.6/1.6
(B-b)×100/b = -37.5
i.e. 37.5% reduction
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