Question

If the length of a rectangular garden is 7 feet longer than is width and the garden’s perimeter is 186 feet, what is the area in square feet?

Answer 1

Answer:

$let \: us \: consider \: width \: of \: rectangle \: be \: \: \: x \: feet \: \\ length \: is \: 7 \: feet \: more \: than \: width \: \\ so \: length \: of \: rectangle \: is \: x + 7 \: feet \\ perimeter \: of \: rectangle = 2 \times (l + b) \\ 186 = 2 \times (x + x + 7) \\ 186 = 2(2x + 7) \\ 186 = 4x + 14 \\ 186 - 14 = 4x \\ 172 =4x \\ 172 \div 4 = x \\ 43 = x \\ width \: of \: rectangle \: = 43 \: feet \\ length = 43 + 7 = 50 \: feet \\ area \: of \: rectangle \: = l \times b \\ area = 43 \times 50 \\ = 2150 \: feet \\ area \: of \: the \: rectangle = 2150 \: feet$

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