if the length of a rhombus is 30 cm and its area 240 sq cm find its perimeter
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Answer:
Here is given,height of one diagonal is 30cm.
And area is 240cm^2.
Step-by-step explanation:
Now,
area of rhombus is-
product of diagonal/2.
Suppose other diagonal is X cm.
Then, (30×X)/2=240
So, X=16cm.
Now, diagonals of rhombus intersect each other at right angle.
So, halfs of the both diagonals are 8cm and 15cm respectively.
Then, 8^2+15^2=(side of rhombus)^2.
8^2+15^2=(side of rhombus)^2.So, side of rhombus is 17cm.
8^2+15^2=(side of rhombus)^2.So, side of rhombus is 17cm.Now, perimeter of rhombus is 4×side.
So, it is equal to 68cm. Ans
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