Question

If the length of a seconds pendulum on a planet is
2 m, then the acceleration due to gravity on the
surface of that planet is ______.
(acceleration due to gravity on the surface of the
Earth = 9.8 ms)

from iit foundation series class 9 physics, Chapter 1, Classroom wing, Very short answer question​

Answer 1

Answer:

sorry I didn't get the answer

Answer 2

Answer:

g = 19.71 m/s²

Explanation:

given:-

l = 2m

since its a seconds pendulum

therefore T = 2sec

by the formula,

T = 2pie(l/g)½

2 = 2 × 3.14 × (2/g)½

g½ = (2 × 3.14 × 1.414)/2

g½ = 4.44996

squaring both sides

g = 19.7132 m/s²