If the length of a simple pendulum is halved its time period will become
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Hi Mate!!!
T1 = k √L
T2 = k √ ( L / 2 )
Dividing both the question
T1 : T2 = √2
T2 = T1 / √2
T1 = k √L
T2 = k √ ( L / 2 )
Dividing both the question
T1 : T2 = √2
T2 = T1 / √2
Answered by
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If the length of a simple pendulum is halved its time period will become decreased by a factor of 2.
- So the period of a pendulum is directly proportional to the square root of its length.
- So, if the length increases, its time period also increases. It means that it takes longer to complete one oscillation.
- So when its length is halved, its time period is decreased by a factor of 2.
- Time taken is, T=2π√l/g
- l is the length of the pendulum and g is the Earth's gravity.
- length is halved then, T1=2π√l/2g
- So T1/T = 1/√2
So the time period is decreased by a factor of 2
#SPJ3
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