If the length of a simple pendulum is increased
by 2%, then the time period
(a) increases by 2% (b) decreases by 2%
(c) increases by 1% (d) decreases by 1%
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Nice Question mate !!!
T = 2π √l/g
applying log and differentiating Or to find differential equation
ΔT/T = 1/2 Δl/l + 1/2 Δg/g
ΔT/T = 1/2 x 2
Time period increases by 1%
:) Hope this helps !!!
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