Question

If the length of a simple pendulum is increased to four times ,the initial length,how is the time period affected?

Answer 1

time period becomes two times of its initial.

it is given that length of a simple pendulum is increased to four times the initial length.

we know,

T = 2π√{l/g}

where l is length of pendulum, T is time period and g is acceleration due to gravity.

here g is constant i.e., g = 10m/s²

so, T ∝ √l , therefore time period of simple pendulum is directly proportional to square root of its length.

if length of simple pendulum is increased to four times.i.e., L = 4l

so, T₁/T₂ = √{l₁/l₂}

⇒T/T₂ = √{l/4l} = 1/2

⇒T₂ = 2T

hence time period becomes two times of its initial.

Answer 2

Explanation:

the answer is upto the mark thanks