Question

if the length of a triangle is (X + 2) cm and breadth is (X + 1) and find the area of a rectangle

options
(x²+2x+3) cm² ਸਮ² सेमी²
(x²+2x+2) cm² ਸਮ² सेमी²
(x²+3x+2) cm² ਸਮ² सेमी²
(x²+3x+3) cm² ਸਮ² सेमी²​

Answer 1

Answer:

see this attachment hope it's helpful to you

Answer 2

Answer:

Let the length of the rectangle be x units and the breadth be y units.

$area \: of \: the \: rectngle = lenth \: \times \: breadth \:x \times y = xysq.units$

From the given we have

(x+2) × (y-2) = xy-28

And (x-1)×(y+2) = xy + 33

(x+2) × (y - 2) = xy - 28

xy-2x+ 2y= - 24

$- x + y = - 12$

$x = y + 12...(i)$

$aslo \: (x - 1) \times (y + 2) = xy + 33$

$xy + 2x - y - 2 = xy + 33$

$2x - y = 35..ii$

Substuting equation i in equation ii

$2x - y = 35$

$2(y + 12) - y = 35$

$y = 11$

Substituting 11 in equation i we get

$x = y + 12$

$x = 11 + 12 \\ x = 23$

✍ Hope it's helpful to you ✍