If the length of a wire is halved and its cross-sectional area is doubled, then what would be the resistance of the wire?
(Given, initially the resistance of the wire is R)
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Answer:
R'=1/4(R)
Explanation:
The resistance of the wire related to length 'l' and area ‘A’ of the conductor is given by-
R=Pl/A whre P is the specific resistance of the conductor
Given l'= l/2
A'= 2A
Hence ,
R'=P(l/2)/2A
= P(l/A)*1/4
R'=1/4(R)
Hence the new resistance will be quarter the value of original resistance
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