Question

If the length of ah is √13 m,and length,breadth,height are in the ratio of 5:4:7,then find TSA of cuboid

Answer 1

Answer:

Answer. 2(lh bh lb) = 504 so, let l = 6x h = 5x b = 3x by substituting the value in the formula, we get 2* (6x * 5x 6x * 3x 5x * 3x) = 504 when we simplify it , we get 2 * 63x ^2 = 504 63x ^2 = 504 / 2 x^2 = 252 / 63 x^2 = 4 i.e, x = 2 by putting the value of x in the given ratio, we get dimenstions i.e, length = 12 breadth = 6 height = 10 and volume = l * b * h i.e, 720 cm ^3 note - here ' * ' means 'multiply', ' ^2 ' means 'square' and ' ^3 ' means 'cube' ~OK~

Answer 2

Answer:

Let the angle be 5x,4x nd 2x.

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=1216

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=1216

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76x²=16

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76x²=16x=4cm.

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76x²=16x=4cm.Dimensions are 20cm,16cm nd 8cm.

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76x²=16x=4cm.Dimensions are 20cm,16cm nd 8cm.Volume=lbh

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76x²=16x=4cm.Dimensions are 20cm,16cm nd 8cm.Volume=lbh=>20*16*8

Let the angle be 5x,4x nd 2x.TSA=2(lb +bh +hl)=12162(20x²+8x²+10x²)=121676x²=1216x²=1216/76x²=16x=4cm.Dimensions are 20cm,16cm nd 8cm.Volume=lbh=>20*16*8=2560cm².