if the length of another wire is made up of same material is 200% more than the first and diameter of second is100% more than, first. findresistance.
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half of the resistance of te second wire. Answer
Resstance of first wire is R1=π(d1/2)2ρl1 and resistance of 2nd wire is R2=π(d2/2)2ρl2
Here, l1=2l2,d1=2d2
Thus,R1=π(2d2/2)2ρ(2l2)=R2/2
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