Question

If the length of chord is 32 cm
and distance of a chord from
the centre of the circle is 12 cm
then the diameter of circle is​

Answer 1

Answer:

40 CM

Step-by-step explanation:

Hi Buddy Your Answer Is  By Pythagoras Theorem

In ∆AOB angle A is 90°

(Reason: Perpendicular drawn from the center of the circle to the chord bisects the chord)

length of the chord= 32/2=16

(OA)²+(AB)²=(OB)²

(12)²+(16)²=(OB)²

144+256=(OB)²

400=(OB)²

OB =20cm

Now,

Diameter = radius ×2

=20×2  =40cm

Therefore the diameter is 40 cm

Hope it will help you

Answer 2

Answer:

r=20 cm

Step-by-step explanation:

As the perpendicular from centre to chord bisects

the chords

thus in the figure

PA=PB=16cm and OP=12 cm

Now in ΔOPB

r=√(OP²+PB²)

=√(144+256)

=√400

r=20 cm