If the length of cuboid is twice its breadth and its height is ,5 units ,then express the total surface area of it in the form of polynomial......
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Let breadth of the rectangle be 2x then length would be x
we have, l=x, b=2x and h = 5
So, TSA of cuboid = 2[lb+bh+hl]
= 2[2x²+10x+5x]
= 2[2x²+15x]
= 4x² + 30x
we have, l=x, b=2x and h = 5
So, TSA of cuboid = 2[lb+bh+hl]
= 2[2x²+10x+5x]
= 2[2x²+15x]
= 4x² + 30x
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