Question

if the length of diagnol of rhombus whose area 216 sq CM is 24 CM then find the length of second diagnol​

Answer 1

Answer:

Area of the rhombus

A = d1d2/2 = 24(d2)/2 = 216

d2 = 216(2)/24 = 18

Answer 2

Given:

• Area of rhombus is 216cm²
• Length of first diagonal is 24cm

To Find:

• Length of another diagonal?

Solution:

We are given that area of rhombus is 216cm² and length of one diagonal is 24cm.

Let suppose that another diagonal of rhombus is x

We know that :

• $\large{\boxed{\bf{Area~of~rhombus~=~ \dfrac{d_{(1)} \times d_{(2)} }{2} }}}$

Where:

• $\large{d_{(1)}}$ = 1st diagonal ••••24cm
• $\large{d_{(2)}}$ = 2nd diagonal •••• x

Let put value in formula:

$\large{\sf{Area~of~rhomus~=~\dfrac{d_{(1)} \times d_{(2)} }{2}}}$

$\implies\large{\sf{216\:=\:\dfrac{24×x}{2}}}$

$\implies\large{\sf{216\:=\:12x}}$

$\implies\large{\sf{x\:=\: \dfrac{216}{12}}}$

$\implies\large{\sf{x\:=\: 18}}$

Therefore,

• $\large{\boxed{\green{\tt{Second\: diagonal\:of\: rhombus\:=\:18cm}}}}$