If the length of diagonal of a cube is 8√3 cm, then find it's surface area.
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Answered by
10
Diagonal of cube = Side × root3
=> Side × root3 = 8 × root3
=> Side of cube = 8 cm
Surface area = 6 a^2
= 6 ( 8)^2
= 6 × 64
= 384 cm^2
=> Side × root3 = 8 × root3
=> Side of cube = 8 cm
Surface area = 6 a^2
= 6 ( 8)^2
= 6 × 64
= 384 cm^2
Answered by
24
Length of diagonal of cube = 8√3
√3 × Edge = 8√3
Edge = (8√3/√3) cm
Edge = 8 cm.
Surface area of cube = 6 × (Edge)²
=> 6 × (8)²
=> 6 × 64
=> 384 cm²
Hence,
Surface area of cube = 384 cm².
√3 × Edge = 8√3
Edge = (8√3/√3) cm
Edge = 8 cm.
Surface area of cube = 6 × (Edge)²
=> 6 × (8)²
=> 6 × 64
=> 384 cm²
Hence,
Surface area of cube = 384 cm².
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