if the length of diagonal of a rhombus is 24 cm and its area is 216 square cm find its perimeter
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HeYa
Here is your Answer:
(1)area of rhombus = 1/2(D1 ×D2)
⇒216= 1/2(24×D2)
⇒D2 = 18 cm
(2) as we know that diagonals bisect each other at 90°
so by phythagoras theorem,
side =√[(12)² + (9)²] = √(144 +81)= √225 = 15 cm
(3)perimeter = 4×side = 4×15 = 60 cm
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