Question

if the length of diagonals in cm of a rhombus are 6x and 8x and its perimeter is 40 cm, then value of 2x is?
please answer this​

Answer 1

Answer:

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Step-by-step explanation:

Let the unit be x so the diagonals are 6x and 8x

let the shorter diagonal be 6x and longer be 8x

the point of intersection of the two digonals to be named as O

so half of the diagonals be 6x/2 and 8x/2

given pmt=40cm

one side=40÷4=10 cm

so all the sides are 10cm respectively (as in Rhombus all the sides are of equal measure)

so According to pythagoras theorm

(6x/2)^2 +(8x)^2 =(10)^2

36x^2/4+64x^2/4=100

100x^2=100×4

100x^2=400

x^2=4

x=2

so length of shorter side is 6x=6×2=12

so length of longer side is 8x = 8 x 2= 16