If the length of
e. Coli dna is 1.36 mm, can you calculate the number of base pairs in
e. Coli?
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4
Answer:
Explanation:
Given,
Length = 1.36mm
Distance b/w them = 0.34x10`9 (constant)
Total length of helix = total base pairs * distance b/w them
1.36 = total base pairs * 0.34x10`9
Total Base pairs = 1.36/0.34*10`9
Total Base pairs = 4x10`6
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