if the length of each edge of a cube inceases by 50%, what is the percentage increase in the total surface area of the cube
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Step-by-step explanation:
Let cube's side is x
Then it's surface area will be 6x²
Now increasing it's side by 50%
New side= (3x/2)
Again surface area= 6×(3x/2)²
= 6x²× 9/4
Now subtracting these to surface area=(9/4–1) × x²
= (5/4) × x²
So it's increased by 5/4
Now for converting it in percentage e know that we have to multiple it with 100
(5/4)×100= 125%
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