Question

if the length of each edge of a cube inceases by 50%, what is the percentage increase in the total surface area of the cube
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Answer 1

Answer:

Percentage of increase in the T.S.A of new cube = 225%

Step-by-step explanation:

Let's assume that the length of each edge of a cube is x.

∴ T.S.A of the cube = 6a²

It is given that each edge increases by 50%,

∴ The new length of each edge = $a+\frac{a}{2}$ = 1.5a

∴ T.S.A of the cube with new length = $6(\frac{3a}{2}) ^{2}$ = 6(1.5a)² = 13.5a²

⇒Percentage of increase

= $(\frac{13.5a^{2} }{6a^{2}}) (100)$

= 225%

∴ Percentage of increase in the T.S.A of new cube = 225%

Hope this helps!