if the length of each side of a triangle is decreased by 20% then what is the percentage decrease in the area of the triangle?
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Area of triangle = A = square root of [s(s-a)(s-b)(s-c) where 2s =a+b+c.
Each side is halved,
s’ = s/2
(s’-a’) = (s-a)/2.
s’-b’) = (s-b)/2.
s’-c’) = (s-c)/2.
New areaA’ = square root of [s(s-a)(s-b)(s-c) /16. = A/ 4.
Change in area = 3/4 A= 75% decrease
Each side is halved,
s’ = s/2
(s’-a’) = (s-a)/2.
s’-b’) = (s-b)/2.
s’-c’) = (s-c)/2.
New areaA’ = square root of [s(s-a)(s-b)(s-c) /16. = A/ 4.
Change in area = 3/4 A= 75% decrease
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36% is correct Answer for this question
36%
36%
36%
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