If the length of median AP of ∆ABC is 9 cm and G is the centroid then find l ( AG ) and l ( GP )
*with solution*
Answers
Answer:
Correct option is
B
8cm
We know that G is centroid of ΔABC
AD=12cm
Centroid → intersection point of medians
Centroid divides median in ratio of 2:1
AD
AG
=
1
2
AG=2AD
AG+GD=12
3GD=12
GD=4cm
AG=8cm.
Given : Length of median AP of ∆ABC is 9 cm and G is the centroid of triangle.
To find : length of AG and GP.
Solution :
Median of a triangle from a vertex is the line that bisects the opposite side of the triangle to the vertex.
A triangle has three medians that bisect the three sides. The intersection of the medians is called centroid of the triangle.
Here, AP is the median and G the centroid of the triangle.
G divides the median in the ratio 1:2.
Since, length of AP is 9 cm, therefore AG:GP = 2:1
Therefore,
length of AG = 2 × 3 = 6 cm.
length of GP = 1 × 3 = 3 cm.