Question

If the length of minute hand of a watch is √7 cm, Find the area swept by it between 9 am to 9: 10 am.

Answer 1

Answer:

11/3 cm^2

Step-by-step explanation:

let the radius of min. hand be root7 cm

ATP,

total area swept by the min. hand to complete 1 hour  = $\pi$ r^2

= 22/7 * root7^2 = 22 cm^2

area swept by the min. hand between 9 o clock am to 9:10 = 1/6 of 22cm^2( 10 min / 60min )

= 11/3 cm^2 = 3 2/3 cm^2

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