if the length of one side of a rhombus is equal to length of one diagonal find the angles of the Rhombus.
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Step-by-step explanation: Let ABCD is a rhombus in which AB=BC=CD=DA=diagonal CA.
In triangle BAC
BA=BC=CA , therefore
angle BAC=angle ABC= angle ACB =60°………(1)
Similarly in triangle DAC , DA=DC=CA , therefore
Angle DAC=angle ACD=angle ADC=60°……….(2)
From eqn. (1) and (2)
Angle A=angle BAC+angle DAC=60°+60°=120°
Angle B= angle ABC = 60°.
Angle C=angle ACB+angle ACD=60°+60°=120°
Angle D =angle ADC=60°.
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