Question

If the length of rectangle is (x+2) cm and breadth is (x+1) cm, find the area of the rectangle.​

Answer 1

Required Solution:-

Here in this question it is stated that, one rectangle is there whose is length is (x + 2) cm and the breadth of that rectangle is (x + 1) cm, and we are asked to find out the area of the rectangle, such that,

• Length of rectangle = (x + 2) cm.
• Breadth of rectangle = (x + 1) cm.
• Area of rectangle = ?

Now we know that the area of rectangle is equal to the product of length of and breadth of the rectangle, in mathematical term,[tex][/tex]

➝ Area of rectangle = length × breadth

By using the area of rectangle formula and substituting all the given values in it, we get:

➝ Area of rectangle = (x + 2) × (x + 1)

➝ Area of rectangle = x² + 3x + 2

Therefore, the area of the rectangle is (x² + 3x + 2) cm².

Answer 2

Answer:

Given :-

• The length of a rectangle is (x + 2) cm and the breadth of a rectangle is (x + 1) cm.

To Find :-

• What is the area of the rectangle.

Formula Used :-

$\clubsuit$ Area Of Rectangle Formula :

$\mapsto \sf\boxed{\bold{\pink{Area_{(Rectangle)} =\: Length \times Breadth}}}$

Solution :-

Given :

$\bigstar\: \: \bf{Length\: of\: Rectangle =\: (x + 2)\: cm}$

$\bigstar\: \: \bf{Breadth\: of\: Rectangle =\: (x + 1)\: cm}$

According to the question by using the formula we get,

$\longrightarrow \bf Area_{(Rectangle)} =\: Length \times Breadth$

$\longrightarrow \sf Area_{(Rectangle)} =\: (x + 2) \times (x + 1)$

$\longrightarrow \sf Area_{(Rectangle)} =\: x(x + 1) + 2(x + 1)$

$\longrightarrow \sf Area_{(Rectangle)} =\: x^2 + x + 2(x + 1)$

$\longrightarrow \sf Area_{(Rectangle)} =\: x^2 + x + 2x + 2$

$\longrightarrow \sf\bold{\red{Area_{(Rectangle)} =\: (x^2 + 3x + 2)\: cm^2}}$

${\small{\bold{\underline{\therefore\: The\: area\: of\: the\: rectangle\: is\: (x^2 + 3x + 2)\: cm^2\: .}}}}$