Question

if the length of rectangle is (x+2) cm and breadth is (x+1) cm find the area of the rectangle give me right ans​

Answer 1

Given

• Length of rectangle ⇒ (x + 2) cm
• Breadth of rectangle ⇒ (x + 1) cm

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To Find

• The area of the rectangle.

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Solution

Formula to Find the Area of Rectangle → Length × Breadth

Length → (x + 2) cm

Breadth → (x + 1) cm

Method 1

Using binomial multiplication, let's find the area of the rectangle.

→ (x + 2)(x + 1)

→ x(x + 1) + 2(x + 1)

→ x² + x + 2x + 2

→ x² + 3x + 2

∴ The area of the rectangle is x² + 3x + 2

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Method 2

Using the identity (x + a)(x + b) = x² + (a + b)² + ab, let's find the area od the rectangle.

Identity → (x + a)(x + b) = x² + (a + b)² + ab

Here,

x = x

a = 2

b = 1

→ (x + 2)(x + 1)

→ (x)² + (2 + 1)(x) + 2(1)

→ x² + 3x + 2

∴ The area of the rectangle is x² + 3x + 2

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Answer 2

Answer:

Given :-

• The length of a rectangle is (x + 2) cm and the breadth of a rectangle is (x + 1) cm.

To Find :-

• What is the area of a rectangle.

Formula Used :-

$\clubsuit$ Area Of Rectangle Formula :

$\mapsto \sf\boxed{\bold{\pink{Area_{(Rectangle)} =\: Length \times Breadth}}}$

Solution :-

Given :

$\bigstar\: \: \bf{Length\: of\: Rectangle =\: (x + 2)\: cm}$

$\bigstar\: \: \bf{Breadth\: of\: Rectangle =\: (x + 1)\: cm}$

According to the question by using the formula we get,

$\longrightarrow \bf Area_{(Rectangle)} =\: Length \times Breadth$

$\longrightarrow \sf Area_{(Rectangle)} =\: (x + 2) \times (x + 1)$

$\longrightarrow \sf Area_{(Rectangle)} =\: x(x + 1) + 2(x + 1)$

$\longrightarrow \sf Area_{(Rectangle)} =\: x^2 + x + 2(x + 1)$

$\longrightarrow \sf Area_{(Rectangle)} =\: x^2 + x + 2x + 2$

$\longrightarrow \sf\bold{\red{Area_{(Rectangle)} =\: (x^2 + 3x + 2)\: cm}}$

${\small{\bold{\underline{\therefore\: The\: area\: of\: a\: rectangle\: is\: (x^2 + 3x + 2)\: cm \: .}}}}$