Question

if the length of rough inclined plane is 10m and the value of g is 10m/s2 and the angle of inclination is 30 degrees and coefficient of friction is 0.1, then the time taken by the block to reach bottom is

Answer 1

Answer:

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Answer 2

The time taken by the block to reach bottom is 2.23 sec.

Explanation:

Given that,

Distance = 10 m

Angle = 30

Coefficient of friction = 0.1

We need to calculate the acceleration

Using balance equation

$mg\sin\theta-\mu mg=ma$

$g\sin\theta-\mu g= a$

Put the value into the formula

$a=10\times\sin30-0.1\times10$

$a=4\ m/s^2$

We need to calculate the time taken by the block to reach bottom

Using equation of motion

$s=ut+\dfrac{1}{2}at^2$

$t=\sqrt{\dfrac{2s}{a}}$

Put the value into the formula

$t=\sqrt{\dfrac{2\times10}{4}}$

$t=2.23\ sec$

Hence, The time taken by the block to reach bottom is 2.23 sec.

Learn more :

Topic : frictional force

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