Question

If the length of shadow of a 15m. high pole is 5√3m.at morning 8am, then what is the angle of elevation of the sunrays with the ground at that time.​

Answer 1

Answer;

Let us take the scenario in the form of a right triangle, where the height of the pole is represented as AB, the shadow of the pole is represented as BC. Let  

∠ C be the angle of Elevation.

So, We know that,

Tan Ф = Opposite / Adjacent

=> Tan Ф = 15 / 15 √ 3

=> Tan Ф = 1 / √ 3

We know that, Tan 30° = 1 / √ 3

So we can say that, Ф = 30°

Hence the angle of Elevation of the sum at that time was 30°.

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