if the length of shadow of a tower is√3 times its height. then the angle with which a person will standing at the end of shadow see the top of the tower
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Consider the height of tower be h ∴ height of shadow =√3h . In a triangle ABC,
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°. Therefore, angle of elevation is 30°.
tan ∠ACB = h / √3h
tan ∠ACB = 1 / √3
∠ACB = 30°. Therefore, angle of elevation is 30°.
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