Question

If the length of tangents from (a, b) to the circles
x2 + y2 - 4x - 5 = 0 and
2² + y2 + 6x - 2y +6 = 0 are equal then
10a - 2b =​

Answer 1

Step-by-step explanation:

t chya mayacha bhosada

phoknicje ho abhyas karat ka na

Answer 2

Answer:

    10a-2b= 11

Step-by-step explanation:

Given circle equations are,

C1:  $x^{2} +y^{2} -4x-5=0$

C2: $x^{2} +y^{2} -6x-2y+6=0$ equidistant

the point P(a,b) , according to the question, is equidistant and tangent from both the circles;

this implies that the point P lies on the radical axis.

The equation of Radical axis is, C1-C2=0

$x^{2} +y^{2} -4x-5 -x^{2} -y^{2} -6x+2y-6=0$

putting P(a,b) in the radical axis equation gives us,

 $-10a+2b-11=0\\ \\ 10a-2b=11$

Therefore, 10a-2b=11