if the length of the conductor is 250 m and its resistivity is 1.6*10^-8 and its resistance is 1ohm . then find the cross sectional area of the conductor and what will be its resistance if the cross sectional area is doubled .
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R=resistivity ×l/A
1=1.6×10^-8×250/A
A=400×10^-8
=4×10^-6
1=1.6×10^-8×250/A
A=400×10^-8
=4×10^-6
jalanshalini:
If area is doubled, resistance gets halfed.
find its resistance too
It's already there in the question i.e. 1ohm
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