if the length of the conductor is doubled without changing its area, then the value of resistance becomes
please prove this for me
Answers
Answered by
9
as resistance R = (rho) l/a
if Length l is doubled keeping area of x-section uniform then resistance will surely get doubled as R(new) = (rho) 2l/a
= 2 (rho)l/a
= 2 R
Hope it helps and if yes please mark as brainliest.
if Length l is doubled keeping area of x-section uniform then resistance will surely get doubled as R(new) = (rho) 2l/a
= 2 (rho)l/a
= 2 R
Hope it helps and if yes please mark as brainliest.
geniuseinsteinn:
hey unusual are you class 9
Answered by
6
lets say length is L and cros section is A = pi * r ^2
Resistance, R = (roh * L)/ (pi * r^2)
if the length and cross section both are doubled then the resistance is
R2 = (roh *2L)/ (pi*4r^2)
Now R2/R = [(roh *2L)/ (pi*4r^2)] / [(roh * L)/ (pi * r^2)]
then R2 = R /2
so, the resistance will be half of previous.
Resistance, R = (roh * L)/ (pi * r^2)
if the length and cross section both are doubled then the resistance is
R2 = (roh *2L)/ (pi*4r^2)
Now R2/R = [(roh *2L)/ (pi*4r^2)] / [(roh * L)/ (pi * r^2)]
then R2 = R /2
so, the resistance will be half of previous.
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