If the length of the cylinder is increased by 2% the area of its base will increase by
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Here volume of the cylinder will be constant
⇒LA=V
⇒L∝1/A
⇒dL/L=-dA/A³
⇒dL/L×100=-dA/A³×100
⇒2=dA/A(-1/A²)×100
⇒dA/A×d/dA(A)×100=2
⇒dA/A=2%
⇒Area will be decreased by 2%
Step-by-step explanation:
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