Question

if the length of the diagonal of a rectangle is 26 CM and the length of its base is 24 CM find the length of the altitude of the rectangle.​

Answer 1

Let ABCD be the rectangle.

l(BC) = 24cm, l(AC) = 26cm

In ∆ABC, m∠ABC = 90° ... [Angle of a rectangle]

∴[l(AC)]2 = [l(AB)]2 + [l(BC)]2 … [Pythagoras theorem]

∴ (26)2 = [l(AB)]2 + (24)2

∴ (26)2 – (24)2 = [l(AB)]2

∴(26 + 24) (26 – 24) = [l(AB)]2 …[∵ a2 – b2 = (a + b)(a – b)]

∴ 50 x 2 = [l(AB)]2

∴100 = [l(AB)]2 i.e. [l(AB)]2 = 100

∴ l(AB) = √100 …. [Taking square root of both sides]

∴ l(AB) =10 cm

∴The length of the other side is 10 cm.

HOPE U HELP THIS

Answer 2

Answer:

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