Question

If the length of the diagonal of a rhombus is 20 cm then find its perimeter.​

Answer 1

Answer:

If the length of the diagonal of a rhombus is 20 cm then its perimeter is 40√2   cm.

Step-by-step explanation:

We know that d=√2s  

Given diagonal = 20 cm  

s = 20/√2  cm

 $\frac{20}{ \sqrt{2} } =\frac{20\sqrt{2} }{\sqrt{2} \times \sqrt{2} } \\= \frac{20\sqrt{2}}{2} \\= 10\sqrt{2}$

Therefore, perimeter of the square is = 4 x  side

= 4 x 10√2  = 40√2   cm.

Hence perimeter of the square is 40√2   cm.

Answer 2

Step-by-step explanation:

We know that d=√2s

Given diagonal = 20 cm

s = 20/√2 cm

\begin{gathered}\frac{20}{ \sqrt{2} } =\frac{20\sqrt{2} }{\sqrt{2} \times \sqrt{2} } \\= \frac{20\sqrt{2}}{2} \\= 10\sqrt{2}\end{gathered}

2

20

=

2

×

2

20

2

=

2

20

2

=10

2

Therefore, perimeter of the square is = 4 x side

= 4 x 10√2 = 40√2 cm.

Hence perimeter of the square is 40√2 cm.