if the length of the diagonals of a rhombas are 16cm and 12 cm,find its area
plz answer with step by step explanation
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100 cm ²
Step-by-step explanation:
the diagnols of rhombus bisect and are perpendicular to each other . So by using phytogorus theorem we will get
6²+8²= s²
36+64= s²
100=s²
s= 10
area is s×s
so, 10×10 = 100 cm ²
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